x-[x/2+23+(x/2+23)/2+15]=40

来源：百度知道编辑：UC知道时间：2024/05/18 00:11:36

x-[x/2+23+(x/2+23)/2+15]=40
==>x-[3*(x/2+23)/2+15]=40
==>x-[3x/4+69/2+15]=40
==>x-3x/4-69/2-15=40
==>x/4=69/2+15+40=69/2+55

==>x=2*69+4*55=138+220=358

全部拆出来得~~~~x-x/2-23-x/4-23/2-15=40~~~得x=358

x-[x/2+23+(x/2+23)/2+15]=40
等式两边同时乘以4，得
4x-[2x+92+x+46+60]=160
4x-[3x+198]=160
x=198+160
x=358

x得358

x^2+x+1=2/(x^2+x) [x+2]/[x+1]-[x+4]/[x+3]-[x+3]/[x+2]+]x+5]/[x+4] ((13 x-x^2)/(x+1)) (x+(13-x)/(x+1))=42 x+x^2+x^3+x^4+x^5+...+x^12=500/12 x-1/x^2+3x+2+6/2+x-x^2-10-x/4-x^2 (x^2+2x-3)/(x^2-9)*(x^2-5x+6)/(3x^2-x-2) x/(x-2) (x-2)/x (2x-8)/x(x-2)=0 1/x-1 +1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-3)(x-4)+1/(x-4)(x-5) 5x/(x^2+x-6)+(2x-5)/(x^2-x-12)=(7x-10)/(x^2-6x+8) 已知道根号(X)+(1/根号X)=2,求根号(X/X^2+3X+1)-根号(X/X^2+9X+X)